A compound 'X' on treatment with Br2 / NaOH, provided C3H9N, which gives positive carbylamine test. Compound 'X' is :

  • Option 1)

    CH_{3}CH_{2}COCH_{2}NH_{2}

  • Option 2)

    CH_{3}CH_{2}CH_{2}CONH_{2}

     

  • Option 3)

    CH_{3}CON(CH_{3})_{2}

  • Option 4)

    CH_{3}COCH_{2}NHCH_{3}

Answers (1)
A admin

 

Addition of ammonia and its derivatives with aldehydes and ketones -

Product formation is favoured due to rapid dehydration of the intermediate to form  > C = NG

G\:\:may\:be\:\:-OH,\:\:-NH_{2},\:\:-NHC_{6}H_{5},\:\:-NHCONH_{2},\:\:etc

- wherein

\xrightarrow[NaOH]{Br_{2}}C_{3}H_{9}N\xrightarrow[KOH]{CHCl_{3}}CH_{3}CH_{2}CH_{2}-NC

Hoff mann's               Carbylamine

Bromaide degradation  Reaction

Must be aride with one carbon more tha is amine [X] is CH_{3}CH_{2}CH_{2}CONH_{2}

 

 

 


Option 1)

CH_{3}CH_{2}COCH_{2}NH_{2}

Option 2)

CH_{3}CH_{2}CH_{2}CONH_{2}

 

Option 3)

CH_{3}CON(CH_{3})_{2}

Option 4)

CH_{3}COCH_{2}NHCH_{3}

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