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  • Tell me? - Limit , continuity and differentiability - JEE Main

\lim_{x\rightarrow 0}\frac{\sin x}{x}  equals

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Answers (1)

best_answer

As we have learned

Limit of product / quotient -

Limit of product is the product of individual limits such that

\lim_{x\rightarrow a}{f(x).g(x)}

=\lim_{x\rightarrow a}{f(x).\lim_{x\rightarrow a}g(x)

also\:\lim_{x\rightarrow a}{kf(x)}

=k\lim_{x\rightarrow a}{f(x)}

\lim_{x\rightarrow a}\frac{f(x)}{g(x)}=\frac{\lim_{x\rightarrow a}f(x)}{\lim_{x\rightarrow a}g(x)}

 

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 \lim_{x\rightarrow \infty } \frac{\sin x}{x}= \lim_{x\rightarrow \infty }\sin x/ \lim_{x\rightarrow \infty } x= \frac{number in [-1,1]}{\infty }

=0

 

 

 

 

 


Option 1)

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Option 2)

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Option 3)

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Option 4)

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Posted by

Himanshu

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