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  • Tell me? The curve x = 4 – 3y – y2 cuts the y-axis into two points P and Q. Then the area enclosed by the y-axis and the portion of the curve which lies between P and Q is

The curve x = 4 – 3y – y2 cuts the y-axis into two points P and Q. Then the area enclosed by the y-axis and the portion of the curve which lies between P and Q is

  • Option 1)

    20 sq. units      

  • Option 2)

    18 sq. units

  • Option 3)

    17 sq. units

  • Option 4)

    none of these

     

 

Answers (1)

best_answer

As we learnt

Area along y axis -

Let y_{1}= f_{1}(x)\, and \, y_{2}= f_{2}(x) be two curve, then area bounded by the curves and the lines

y = a and y = b is

A=\int_{a}^{b}\left ( x_{2}-x_{1} \right )dy

- wherein

 

 

Required area=\int_{-4}^{1}xdy

                        =\int_{-4}^{1}\left ( 4-3y-y^{2} \right )dy=20\frac{5}{6}\, sq.units


Option 1)

20 sq. units      

Option 2)

18 sq. units

Option 3)

17 sq. units

Option 4)

none of these

 

Posted by

Plabita

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