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Q

The current in a wire varies with time according to the equation I = 4 + 2t, where I is in ampere and t is in sec. The quantity of charge

Answers (1)
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N Neetan

As we learnt

 

Total charge flowing -

 

dQ=Idt\Rightarrow \int dQ=\int Idt

Q=\int Idt

- wherein

Q\rightarrow Total charge

 

 

 

Let dq be the charge which has passed in a small interval of time dt,

 then dq = idt = (4 + 2t)dt
Hence total charge passed between interval t = 2 sec and t = 6 sec
q = \int\limits_2^6 {(4 + 2t)dt} $ = 48 coulomb
 


Option 1)

60 coulomb

Option 2)

24coulomb

Option 3)

48 coulomb

Option 4)

30 coulomb

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