Q

# The current in a wire varies with time according to the equation I = 4 + 2t, where I is in ampere and t is in sec. The quantity of charge

4 Views

As we learnt

Total charge flowing -

$dQ=Idt\Rightarrow \int dQ=\int Idt$

$Q=\int Idt$

- wherein

$Q\rightarrow$ Total charge

Let dq be the charge which has passed in a small interval of time dt,

then dq = idt = (4 + 2t)dt
Hence total charge passed between interval t = 2 sec and t = 6 sec
q = $\int\limits_2^6 {(4 + 2t)dt}$ = 48 coulomb

Option 1)

60 coulomb

Option 2)

24coulomb

Option 3)

48 coulomb

Option 4)

30 coulomb

Exams
Articles
Questions