The electronic configuration of copper is:
[Ar]3d104s1
[Ar]3d94s2
[Ar]3d104s2
[Ar]3d84s2
Ideally, the electronic configuration of Cu must be [Ar] 3d9 4s2 but in this case, the electrons in d-orbitals are not symmetrically filled. Thus to maintain the symmetricity, one electron from 4s-orbital goes to the d-orbital and thus Cu maintains the electronic configuration as [Ar] 3d10 4s1.
Therefore, Option(1) is correct
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