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The focal lengths of the objective and eye lenses of a telescope are respectively \mathrm{200\ cm} and \mathrm{5\ cm}. The maximum magnifying power of the telescope will be:

Option: 1

-40


Option: 2

-48


Option: 3

-60


Option: 4

-100


Answers (1)

best_answer

Magnifying power is maximum when image is formed at the least distance of distinct vision.
\mathrm{M=-\frac{f_0}{f_e}\left(1+\frac{f_e}{D}\right)=-\frac{200}{5}\left(1+\frac{5}{25}\right)=-48}

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Kuldeep Maurya

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