The ha;f life period of a first order reaction is 10 mins. The amount of substance left after 40 mins will be :

Answers (1)
S Sayak

Number of half lives spent = 40/10 = 4

Let initial amount be m

Final amount is m'

\\m'=m\left (\frac{1}{2} \right )^{4}\\ m'=\frac{m}{16}

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