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  • The hydrogenation of vegetable ghee at 25oC reduces the pressure of H2 from 2atm to 1.2 atm in 50 min. Calculate the rate of reaction in terms of change of pressure per m

The hydrogenation of vegetable ghee at 25oC reduces the pressure of H2 from 2atm to 1.2 atm in 50 min. Calculate the rate of reaction in terms of change of pressure per minute.

Option: 1

1.6 \times 10^{-2} \mathrm{\: atm\: } \mathrm{min}^{-1}


Option: 2

0.8 \times 10^{-2} \mathrm{\: atm\: } \mathrm{min}^{-1}


Option: 3

16 \times 10^{-2} \mathrm{\: atm\: } \mathrm{min}^{-1}


Option: 4

3.2 \times 10^{-2} \mathrm{\: atm\: } \mathrm{min}^{-1}


Answers (1)

best_answer

Pressure: For gaseous reactants rate varies with pressure just like concentration.
\frac{\mathrm{d} \mathrm{x}}{\mathrm{dt}} \propto \text {Pressure }(\text {as } \mathrm{P} \propto \mathrm{C})

\\\text { Rate of reaction }=\frac{\text { Change in pressure }}{\text { Time in min }} \\\\ \text { Rate of reaction }=\frac{2-1.2}{50}
                                      =\frac{0.8}{50}=1.6 \times 10^{-2} \mathrm{\: atm\: } \mathrm{min}^{-1}

Therefore, option(1) is correct.

Posted by

Devendra Khairwa

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