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  • The length of a wire of a potentiometer is 100cm and emf of its standard cell is E volt.It is employed to measure the emf of a battery whose internal resistance is 0.5<img alt="\Omega" src="https:/

The length of a wire of a potentiometer is 100cm and emf of its standard cell is E volt.It is employed to measure the emf of a battery whose internal resistance is 0.5\Omega. If the balance point is obtained at l=30cm from the positive end,emf of the battery is

Option: 1

\frac{30E}{100}


Option: 2

\frac{30E}{100.5}


Option: 3

\frac{30E}{100-0.5}


Option: 4

\frac{30\left ( E-50i \right )}{100}


Answers (1)

best_answer

As we learnt

 

Potential gradient -

 

Potential difference per unit length of wire    

- wherein

x=\frac{V}{L}

 

 

Using the principle of potentiometer v\alpha l

\frac{V}{E}= \frac{l}{L}\: \: or\: \: V=\frac{l}{L}E= \frac{30E}{100}

Posted by

SANGALDEEP SINGH

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