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The magnitude of the earth's magnetic field at a place is Bo and the angle of dip is δ. A horizontal conductor of length l lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is

Option: 1

 Zero                                         


Option: 2

Bolvsinδ


Option: 3

Blv

                  


Option: 4

Bolvcosδ


Answers (1)

best_answer

 

 

 When a conductor lying along the magnetic north-south, moves eastwards it will cut vertical component of Bo. So induced emf   

                            e=vB_Vl

                                =v(B_0 sin\delta. l)

                                =B_0. l. v.sin\delta

.

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