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The potential (in V) of a hydrogen electrode \mathrm{\left ( P_{H_2} \textrm{= 1 atm}\right )} in a solution with pH = 5 at 25oC is :

Option: 1

0.295


Option: 2

-0.295


Option: 3

-0.59


Option: 4

0.59


Answers (1)

E = 0-0.059\log\left ( \frac{1}{[H^+]} \right )

\mathrm {E=-0.059 \times pH}
\mathrm E=-0.059 \times 5=-0.295 \mathrm{\: V}

Therefore,option(2) is correct

Posted by

Sumit Saini

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