The ratio between the values of accelaration due to gravity at a height 1km above and at a depth of 1km below the earth's surface is (radius of earth is R)

Answers (1)
M manish

We know that,
variation in g with height "h"

g^{'} = g\left ( \frac{R}{R+h} \right )^2

g'\rightarrow gravity at height h from surface of earth.

R\rightarrow Radius of earth

h\rightarrow height above surface

g'\alpha\, \frac{1}{r^{2}}

 Acceleration due to gravity above the earth  (g_{1})    = g_{o}\left ( 1-\frac{2h}{R} \right )..............(i)

Since h<<R acceleration due to gravity below earth surface g_{2}=g_{o}\left ( 1-\frac{d}{R} \right )...........(ii)

Now, put d = h = 1 km
Thus, \frac{g_1}{g_2}=\frac{R-2}{R-1}

Preparation Products

Knockout KCET 2021

An exhaustive E-learning program for the complete preparation of KCET exam..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout KCET JEE Main 2021

It is an exhaustive preparation module made exclusively for cracking JEE & KCET.

₹ 27999/- ₹ 16999/-
Buy Now
Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
Buy Now
Test Series JEE Main Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
Buy Now