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The reaction 

\mathrm{2RCOCl+R^{'}_{2}Cd\rightarrow 2RCOR^{'}+CdCl_{2}}

follows the mechansim

Option: 1

S_{Ni}


Option: 2

E_{1cb}


Option: 3

S_{N1}


Option: 4

S_{N2} with a tetrahedral intermediate


Answers (1)

best_answer

There is a SN2 reaction with a tetrahedral intermediate to form Ketone

\mathrm{2RCOCl+R'_{2}Cd\rightarrow 2RCOR'+CdCl_{2}}

Thus in the given reaction 

there is a SN2 reaction with a tetrahedral intermediate

Hence, the correct answer is Option (4)

Posted by

seema garhwal

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