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The solubility product of Pbl_{2} is 8.0 \times 10^{-9}. The solubility of lead iodide in 0.1 molar solution of lead nitrate is x \times 10^{-6} mol/L. The value of x is ______. (Rounded off to the nearest integer) [Given \sqrt{2}=1.41]
Option: 1 141
Option: 2 -
Option: 3 -
Option: 4 -

Answers (1)

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Answer : 141

Posted by

sudhir.kumar

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