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The volume of a colloidal particle, V_{c} as compared to the volume of a solute particle in a true solution V_{s}   could be

Option: 1

\sim 1\;


Option: 2

\; \sim 10^{23}\;


Option: 3

\; \sim 10^{-3}\;


Option: 4

\; \sim 10^{3}


Answers (1)

best_answer

The range of diameter is between 1 and 1000 nm for a colloidal particle.

The particle size of the colloidal particle is 1 nm to 1000 nm, let it be 10 nm.

And particle size of the true solution particle is 1 nm 

\mathrm{\therefore \frac{V_{c}}{V_{s}} = \frac{\frac{4}{3} \pi \left ( 10 \right )^{3}}{\frac{4}{3}\pi \left ( 1 \right )^{3}} \simeq 10^{3}}

Therefore, option number (4) is correct.

Posted by

Devendra Khairwa

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