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  • There are 5 identical objects in a group, m is the number of arrangement of these object. There are 10 objects in another group, of which 7 are alike, and the rest three are distinct. Let n be numb

There are 5 identical objects in a group, m is the number of arrangement of these object. There are 10 objects in another group, of which 7 are alike, and the rest three are distinct. Let n be number of arrangement of these objects then 

Option: 1

m + n = 721 


Option: 2

mn = 721 


Option: 3

m + n =  720 


Option: 4

n - m = 721 


Answers (1)

best_answer

PERMUTATION OF OBJECTS WHEN FEW ARE IDENTICAL

If there n objects of which p objects are of one type, q objects of another type, r objects of yet another type and all others are distinct, the total number of ways of arranging all the objects is \\\mathrm{\frac{n!}{p!q!r!}}

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m = 5! / 5! = 1 ( Can also tell that this equals 1 as all objects are alike )

n = 10 !/ 7 ! = 720

So m + n = 721

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Sayak

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