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Three blocks are in contact as shown in figure. All the surfaces are frictionless. The value of reaction forces between 2 kg and 3 kg blocks and 3 kg and 5 kg blocks respectively (in N)-

Option: 1

10,8


Option: 2

8,6


Option: 3

8,5


Option: 4

6,8


Answers (1)

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Solution

Let's assume the acceleration of the blocks be a, and reaction force be N1 and N2. F.B.D of all the blocks combined-

F=ma\\ \\ a=\frac{10}{10}=1m/s^2

F.B.D of block of mass 2 kg-

F_{net}=ma

10-N_{1}=2\times1\\ \Rightarrow N_{1}=8N

F.B.D of block of mass 5 kg-

F_{net}=ma

N_{2}=5\times1=5N

Posted by

Devendra Khairwa

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