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Three people A, B, C have to deliver a guest lecture one by one. Then the number of ways in which it can be done is 

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

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They can deliver lecture in following sequences,

 ABC , ACB , BCA , BAC , CAB , CBA 

To calculate it without actually listing each of them, we can use Multiplication rule

To decide the order of giving speech, we have to do 3 tasks

1. Decide who gives the speech first, AND

2. Decide who gives the speech second, AND

3. Decide who gives the speech third

Number of ways of doing first task is 3 (any of the three can give the speech first)

Number of ways of doing second task is 2 (any of the remaining 2 can give the speech second)

Number of ways of doing third task is 1 (only one person left)

As, we have to do all three tasks (AND used), so multiplication rule

So, total number of ways = 3 x 2 x 1 = 6 ways

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shivangi.bhatnagar

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