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Total number of proper divisor of 3600 is 

Option: 1

41 


Option: 2

42 


Option: 3

43 


Option: 4

44 


Answers (1)

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As we have learned

Factors of Numbers: 

Let n=p_{1}^{n_1}p_{2}^{n_2}.........p_{k}^{n_k}.

The total number of  proper divisors are (1+n_{1})(1+n_{2})(1+n_{3})..........- 1.

The number itself is not a proper divisor of itself

 

Now,

 3600 = 2 ^4 \cdot 3 ^2 \cdot 5 ^2

no. of divisor = (4+1)(2+1)(2+1)-1 = 44 

 

Posted by

shivangi.bhatnagar

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