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Total power of an Amplitude Modulated wave depends upon 

Option: 1

 Amplitude of carrier waves only 


Option: 2

Modulation Index only 


Option: 3

Both 1 and 2 


Option: 4

Neither 1 nor 2


Answers (1)

best_answer

As we have learned

Total power of AM wave -

P_{total }= P_{c}+P_{sb}

=\frac{E{_{c}}^{2}}{2R} \left ( 1+\frac{m{_{a}}^{2}}{2} \right )

- wherein

m_{a}= modulation index

E_{c}= amplitude of carrier waves

R = Resistance

 

 

A typical Amplitude Modulates wave is given by 

V = V_c \sin w_c t+ \frac{mV_c}{2} \cos (w_c-w_m)t - \frac{mV_c}{2}\cos (w_c +w_m)t

Thus total power = \frac{V_c^2}{R}+\frac{(m/2 V_c)^2}{R}+\frac{(m/2 V_c)^2}{R}

P_T= \frac{V_c^2}{R}+\frac{m^2 V_c^2}{4R}+\frac{m^2 V_c^2}{4R}

P_T= \frac{V_c^2}{R}\left ( 1+ \frac{m^2}{2} \right )             Where m = MOdulation index 

                                                                   V_c = amplitude of carrier wave 

 

 

 

 

 

 

 

Posted by

himanshu.meshram

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