A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are :

  • Option 1)

    300 V, 15 A

  • Option 2)

    450 V, 15 A

  • Option 3)

    450 V, 13.5 A

  • Option 4)

    600 V, 15 A

 

Answers (1)

P_{in}=I_{P}V_{P}\Rightarrow T_{P}=\frac{P_{in}}{V_{P}}=\frac{3000W}{200N}=15A

Efficiency of the transformer

\eta=\frac{P_{out}}{P_{in}}=\frac{V_{s}I_{s}}{V_{P}I_{P}}\Rightarrow \frac{90}{100}=\frac{6V_{s}}{3000}

V_{s}=\frac{90\times 5000}{100\times 6}=450V


Option 1)

300 V, 15 A

This is incorrect option

Option 2)

450 V, 15 A

This is correct option

Option 3)

450 V, 13.5 A

This is incorrect option

Option 4)

600 V, 15 A

This is incorrect option

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