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A wave in a string has an amplitude of 2 cm. The wave travels in the +ve direction of x-axis with a speed of 128 m/sec and it is noted that 5 complete waves fit in 4 m length of the string. The equation describing the wave is

  • Option 1)

    y = (0.02) m sin (15.7x - 2010t)

  • Option 2)

    y = (0.02) m sin (15.7x + 2010t)

  • Option 3)

    y = (0.02) m sin (7.85x - 1005t)

  • Option 4)

    y = (0.02) m sin (7.85x + 1005t)

 

Answers (1)

best_answer

As discussed in concept

Travelling Wave Equation -

y=A sin left ( Kx-omega t 
ight )
 

- wherein

K=2pi /lambda

omega = frac{2pi }{T}

lambda =  wave length

T = Time period of oscillation

 

A = 2 cms   w / k = 128ms-1 S\lambda= 4 \lambda= 4/5

Y = A sin (kx - wA)

K = 2\pi / \lambda = 2\pi\times 5 / 4 = 7.85

Y = 0.02 m sin ( 7.85x - 1005 A )

W = 128 \times 7.85 = 1005


Option 1)

y = (0.02) m sin (15.7x - 2010t)

Incorrect

Option 2)

y = (0.02) m sin (15.7x + 2010t)

Incorrect

Option 3)

y = (0.02) m sin (7.85x - 1005t)

Correct

Option 4)

y = (0.02) m sin (7.85x + 1005t)

Incorrect

Posted by

Aadil

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