# If $\dpi{100} \Theta _{i}$ is the inversion temperature, $\dpi{100} \Theta _{n}$  is the neutral temperature, $\dpi{100} \Theta _{c}$ is the temperature of the cold junction, then Option 1) $\Theta _{i}+\Theta _{c}=\Theta _{n}\;$ Option 2) $\; \Theta _{i}-\Theta _{c}=2\Theta _{n}\;$ Option 3) $\; \frac{\Theta _{i}+\Theta _{c}}{2}=\Theta _{n}\;$ Option 4) $\; \; \Theta _{c}-\Theta _{i}=2\Theta _{n}$

V Vakul

As we have learned

$\theta _n = \frac{\theta _1+\theta _c}{2}$

Option 1)

$\Theta _{i}+\Theta _{c}=\Theta _{n}\;$

Option 2)

$\; \Theta _{i}-\Theta _{c}=2\Theta _{n}\;$

Option 3)

$\; \frac{\Theta _{i}+\Theta _{c}}{2}=\Theta _{n}\;$

Option 4)

$\; \; \Theta _{c}-\Theta _{i}=2\Theta _{n}$

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