Get Answers to all your Questions

header-bg qa

Homolytic fission of the following alkanes forms free radicals 

CH_{3}-CH_{3},CH_{3}-CH_{2}-CH_{3},\left ( CH_{3} \right )_{2}CH-CH_{3},CH_{3}-CH_{2}-CH\left ( CH_{3} \right )_{2}. 

Increasing order of stability of the radicals is

  • Option 1)

    \left ( CH_{3} \right )_{3}\dot{C}<\left ( CH_{3} \right )_{2}\dot{C}-CH_{2}CH_{3}<CH_{3}-\dot{C} H-CH_{3}<CH_{3}-\dot{C}H_{2}

  • Option 2)

    \left ( \dot{C}H_{3} \right )_{2}\dot{C}-CH_{2}CH_{3}<CH_{3}-\dot{C}H-CH_{3}<CH_{3}-\dot{C}H_{2}<\left ( CH_{3} \right )_{3}\dot{C}

  • Option 3)

    CH_{3}-\dot{C}H_{2}<CH_{3}-\dot{C}H-CH_{3}<\left ( CH_{3} \right )_{2}\dot{C}-CH_{2}-CH_{3}<\left ( CH_{3} \right )_{3}\dot{C}

  • Option 4)

    CH_{3}-\dot{C}H_{2}<CH_{3}-\dot{C}H-CH_{3}<\left ( CH_{3} \right )_{3}\dot{C}<\left ( CH_{3} \right )_{2}\dot{C}-CH_{2}CH_{3}

 

Answers (1)

best_answer

As we learnt in

Stability of alkyl free radical -

Electron donating group stabilises alkyl free radicals and withdrawing group destabilises alkyl free radicals.

- wherein

 

 More is the number of hyper conjugative structure, the greater is the stability.

 


Option 1)

\left ( CH_{3} \right )_{3}\dot{C}<\left ( CH_{3} \right )_{2}\dot{C}-CH_{2}CH_{3}<CH_{3}-\dot{C} H-CH_{3}<CH_{3}-\dot{C}H_{2}

Incorrect

Option 2)

\left ( \dot{C}H_{3} \right )_{2}\dot{C}-CH_{2}CH_{3}<CH_{3}-\dot{C}H-CH_{3}<CH_{3}-\dot{C}H_{2}<\left ( CH_{3} \right )_{3}\dot{C}

Incorrect

Option 3)

CH_{3}-\dot{C}H_{2}<CH_{3}-\dot{C}H-CH_{3}<\left ( CH_{3} \right )_{2}\dot{C}-CH_{2}-CH_{3}<\left ( CH_{3} \right )_{3}\dot{C}

Correct

Option 4)

CH_{3}-\dot{C}H_{2}<CH_{3}-\dot{C}H-CH_{3}<\left ( CH_{3} \right )_{3}\dot{C}<\left ( CH_{3} \right )_{2}\dot{C}-CH_{2}CH_{3}

Incorrect

Posted by

divya.saini

View full answer