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  • Try this! Two think dielectric slabs of dielectric constants K1 and K2 (K1<K2) are insertedbetween plates of a parallel plate capacitor, as shown in the figure. The variation ofelectric field 'E' between the plates with distance 'd

Two think dielectric slabs of dielectric constants K1 and K2 (K1<K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field 'E' between the plates with distance 'd' as measured from plate P is correctly shown by :

 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

Answers (1)

best_answer

As we have learned in @9718

Electric field, E\:\alpha \:\frac{1}{K}

As K1 < K2  , so E1 >E2


Option 1)

This option is incorrect

Option 2)

This option is incorrect

Option 3)

This option is correct

Option 4)

This option is incorrect

Posted by

divya.saini

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