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A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth surface and fires 10 shots horizontally , in 5 s. Each bullet has a mass of 10 g with a muzzle velocity of 800ms^{-1}. The final velocity acquired by the person and the average force exerted on the person are

  • Option 1)

    -1.6ms^{-1};\: 8 N

  • Option 2)

    -0.08ms^{-1}; 16 N

  • Option 3)

    -0.8ms^{-1}; 8 N

  • Option 4)

    -1.6ms^{-1};16 N

 

Answers (1)

best_answer

As discussed in 

Work Energy Theorem -

Work done by all the forces acting on a particle equal to change in kinetic energy.

-

 

 MV+mnv=0

V=\frac{mnv}{M}=\frac{-0.01\times 10\times 80}{100}= -0.8ms^{-1}

From work energy theorem

F_{av}\times S_{av} = \frac{1}{2}mv_{rms}^{2}

\Rightarrow \frac{Fav V_{max 1}}{2} = \frac{1}{2} \frac{mV^{2}_{rms}}{2} \Rightarrow fav = 8N


Option 1)

-1.6ms^{-1};\: 8 N

This solution is incorrect

Option 2)

-0.08ms^{-1}; 16 N

This solution is incorrect

Option 3)

-0.8ms^{-1}; 8 N

This solution is correct

Option 4)

-1.6ms^{-1};16 N

This solution is incorrect

Posted by

Aadil

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