Two communicated cylindrical tubes contain mercury. The diameter of one vessel is four times larger than the diameter of the other. A column of water of height 70 cm is poured into the narrow vessel. How much will the mercury level rise in the other vessel and how much will it sink in the narrow one?
4.8 cm and 0.3 cm respectively
0.3 cm and 4.8 cm respectively
4.8 cm in both
0.3 cm for both
Let x=rise of Hg level in the broad vessel, y= drop of Hg level in the narrow vessel. Then,
Equating pressures at A and B on the same horizontal plane,
we get,
So, x= 0.3 cm and y = 4.8 cm
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