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Two communicated cylindrical tubes contain mercury. The diameter of one vessel is four times larger than the diameter of the other. A column of water of height 70 cm is poured into the narrow vessel. How much will the mercury level rise in the other vessel and how much will it sink in the narrow one? 

Option: 1

4.8 cm and 0.3 cm respectively


Option: 2

0.3 cm and 4.8 cm respectively


Option: 3

4.8 cm in both


Option: 4

0.3 cm for both


Answers (1)

best_answer

 

Let  x=rise of Hg level in the broad vessel,  y= drop of Hg level in the narrow vessel. Then,   x A_{1}=y A_{2} \Rightarrow 16 x=y

Equating pressures at A and B on the same horizontal plane,

we get, 

70 \times 1 \times g=(x+y) \times 13.6 \times g \Rightarrow x+y=\frac{70}{13.6}

So, x= 0.3 cm and y = 4.8 cm

Posted by

Rishabh

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