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  • Two magnets of equal mass are joined at right angle to each other as shown. Magnet 1 has a magnetic moment 3 times that of magnet 2. This arrangement is pivoted so that it if free to rotate in the

Two magnets of equal mass are joined at right angle to each other as shown. Magnet 1 has a magnetic moment 3 times that of magnet 2. This arrangement is pivoted so that it if free to rotate in the horizontl plane. In equillibrium what angle will the magnet 1 subtend with the meridian ?

Option: 1

\tan^{-1}\left(\frac{1}{2} \right )


Option: 2

\tan^{-1}\left(\frac{1}{3} \right )


Option: 3

\tan^{-1}(1)


Option: 4

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Answers (1)

best_answer

As we have learnt,

 

Magnet in Equilibrium -

MB_{H}Sin\Theta =MBSin(90-\Theta ) B=B_{H}tan\Theta (tangent law)

- wherein

 

 For equillibrium of the system torques on M1 and M2 due to BH must counter balance each other, i.e,

 M_1 \times B_H = M_2 \times B_H.

If \Theta is the angle between M1 and BH, then angle betwen M2 and BH will be (90 - \Theta). So,

 M_1B_H\sin\Theta =M_2B_H\sin(90 -\Theta)\\ \\*\Rightarrow \tan\Theta = \frac{M_2}{M_1} = \frac{M}{3M} = \frac{1}{3} \Rightarrow \Theta = \tan^{-1}\left(\frac{1}{3} \right )

 

Posted by

Divya Prakash Singh

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