Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Two masses $m_1$ and $m_2$ at a distance $r$

If $m_{1}> m_{2}$

And $I_1$ And $I_2$ are Moment of inertia of masses $m_1$ and $m_2$ respectively about an axis passing through their $COM$ and perpendicular to the line joining them. Then which relation is correct.

Option: 1
$I_{1}> I_{2}$

Option: 2
$I_{1}< I_{2}$

Option: 3
$I_{1}= I_{2}$

Option: 4
Can’t say

Answers (1)

best_answer

As $r_{1}=\frac{m_{2}}{m_{1}+m_{2}}\ast r$ and $r_{2}=\frac{m_{1}}{m_{1}+m_{2}}\ast r$

And $I_{1}=m_{1}r_{1}^{2}$ and $I_{2}=m_{2}r_{2}^{2}$

And $I=\frac{m_{1}m_{2}}{m_{1}+m_{2}}\ast r^{2}$

And $I_{1}=m_{2}I$ and $I_{2}=m_{1}I$

So As $m_{1}> m_{2}$

So, $I_{1}< I_{2}$

Posted by

seema garhwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

0.1 M acetic acid solution having pH =3 is titrated against 0.05 M NaOH solution. Calculate pH at 1/4th stage of neutralization of acid.Option: 1

0.25×60+0.10x=0.15×(60+x)

Trending Articles/News

anam-khan

JAC Chandigarh Counselling 2025: Round 1 seat allotment result out for BTech admissions

anam-khan

JoSAA round 5 seat allotment result 2025 out on josaa.nic.in

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today

Latest Question