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Two masses m1  and m2 are attached to the ends of massless string as shown in fig. Here m1  10 Kg  and \theta = 37 \degree then what should be the mass m2 ofr the system to be in equilibrium . Assume that there is no friction b/w m1  and inclined plane .

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Let the tension in the wire be T

As the system is in equilibrium acceleration of the blocks = 0

Equating the forces on the first block along the direction of Tension we have

\\T=m_{1}g sin\theta \\ T=10\times 9.8\times \frac{3}{5}\\ T=58.8\ N

Equating the forces on the first block in the vertical direction

\\T=m_{2}g\\ 58.8=m_{2}\times 9.8\\\ m_{2}=6\ kg

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