# Two masses m1  and m2 are attached to the ends of massless string as shown in fig. Here m1  10 Kg  and  then what should be the mass m2 ofr the system to be in equilibrium . Assume that there is no friction b/w m1  and inclined plane .

Let the tension in the wire be T

As the system is in equilibrium acceleration of the blocks = 0

Equating the forces on the first block along the direction of Tension we have

$\\T=m_{1}g sin\theta \\ T=10\times 9.8\times \frac{3}{5}\\ T=58.8\ N$

Equating the forces on the first block in the vertical direction

$\\T=m_{2}g\\ 58.8=m_{2}\times 9.8\\\ m_{2}=6\ kg$

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