# Two small balls having equal positive charge Q (coulomb) on each are suspended by two insulated string of equal length L meter, from a hook fixed to a stand. The whole set up is taken in satellite into space where there is no gravity (state of weight less ness). Then the angle between the string and tension in the string is

As we learned

Coulombic force -

$\dpi{100} F\propto Q_{1}Q_{2}=F\propto \frac{Q_{1}Q_{2}}{r^{2}}=F=\frac{KQ_{1}Q_{2}}{r^{2}}$

- wherein

K - proportionality Constant

Q1 and Q2 are two Point charge

In case to weight less ness following situation arises.  So

$angle\; \; \theta =180^{\circ}\; and\; force\; F=\frac{1}{4\pi \varepsilon _{0}}.\frac{Q^{2}}{(2L)^{2}}$

Exams
Articles
Questions