Q

# VITEEE - In figure below R = 200 ohm and on connecting 3V battery in the circuit, the barrier potential developed in diode is 0.5 V.

The value of current in the circuit is

1. 15 mA

2. 17.5 mA

3. 12.5 mA

4. 25 mA

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Barrier Potential developed = 0.5 V

Potential difference across the resistor = 3 - 0.5 = 2.5 V

Current in the circuit is I

$\\I=\frac{2.5}{200}\\ I=12.5\ mA$

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