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  • Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at second after its fall to the next droplet is <img alt="34.3 \mathr

Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4^{\text {th }} second after its fall to the next droplet is 34.3 \mathrm{~m}. At what rate the droplets are coming from the tap ? (Take \mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2})
 
Option: 1 3 drops / 2 seconds
 
Option: 2 2 drops / second
 
Option: 3 1 drop / second

 
Option: 4 1 drop / 7 seconds

Answers (1)

best_answer

Droplets are falling from open tap at after regular time interval, so this distance
Covered will be in Galiko's ratio

Drop 1 is faling in air for 46
\therefore S_{1}= \frac{1}{2}\times 9\cdot 8\times \left ( 4 \right )^{2}
 S_{1}=8\times 9\cdot 8
= 78\cdot 4\, m

\text{Drop 2 is falling air for} \left ( 4-t \right )s
S_{2}= \frac{1}{2}\times 9\cdot 8\times \left ( 4-t \right )^{2}
But S_{1}= S_{2}= 34\cdot 3m\cdots Given
\therefore 78\cdot 4-\frac{1}{2 }\times9\cdot 8\left ( 4-t \right )^{2}= 34\cdot 3
t = ls
t \rightarrow time between two successive drops

Posted by

vishal kumar

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