What is the equation of line that belongs to the family of lines (x+y+1) + (x) = 0 and (x-y+1) + (y) = 0 ?
x+y+1 = 0
x-y +1 = 0
x-y-1=0
x+y-1 = 0
For point of intersection of the first family of lines, solve x + y + 1 = 0 and x = 0 simultaneously. We get (0,-1)
And for second family, solve x - y +1 = 0 and y = 0. We get (-1, 0)
Thus a line which belongs to both the families should pass through both (0,-1) and (-1, 0)
Such a line (using two point form) is x + y + 1 = 0
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