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What is the minimum thickness of a soap film needed for constructive interference in reflected light, if the light incident on the film is of \mathrm{750 \mathrm{~nm}}? Assume that the index for the film is \mathrm{\mu=1.33} :

Option: 1

282 nm


Option: 2

70.5 nm


Option: 3

141 nm


Option: 4

387 nm


Answers (1)

best_answer

\mathrm{Here, 2 \mu \mathrm{t}=\frac{\lambda}{2} }

\therefore \quad \mathrm{t}_{\min }=\frac{\lambda}{4 \mu}=141 \mathrm{~nm}

Posted by

Shailly goel

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