An antifreeze solution is prepared from 222.6\; g of ethylene glycol  (C_{2}H_{6}O_{2})  and 200\; g of water. Calculate the molality of the solution. If the density of the solution is 1.072 \; g\; mL^{-1} then what shall be the molarity of the solution?

Answers (1)

For finding molality we need to find the moles of ethylene glycol.

 \text{Moles of ethylene glycol }= \frac{222.6}{62}= 3.59\ mol

We know that :

                                                      Molality = \frac{Moles\ of\ ethylene\ glycol}{Mass\ of\ water}\times100

                                                                               = \frac{3.59}{200}\times100 = 17.95\ m

Now for molarity :- 

           Total mass of solution = 200 + 222.6 = 422.6 g

           \text{Volume of solution}= \frac{422.6}{1.072}= 394.22\ mL

           \text{So molarity }= \frac{3.59}{394.22}\times1000= 9.11\ M

Most Viewed Questions

Preparation Products

JEE Foundation + Knockout JEE Main 2025 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
JEE Foundation + Knockout JEE Main 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
Knockout JEE Main April 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
Buy Now
Knockout JEE Main May 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
Buy Now
Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions