Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • What is the radius of the director circle of <img alt="x^2 + y^2 - 6x + 6y +11 = 0 ?" src="https://entrancecorner.oncodecogs.com/gif.latex?x%5E2%20&plus;%20y%5E2%20-%206x%20&plus;%206y

What is the radius of the director circle of x^2 + y^2 - 6x + 6y +11 = 0 ?

Option: 1

\sqrt 7


Option: 2

\sqrt {14 }


Option: 3

7 


Option: 4

14 


Answers (1)

best_answer

As we have learned

Radius of director circle is \sqrt{2} times the radius of given circle.

 

Now,

The radius for the given circle

 \\\sqrt {3^2 + 3^2 -11} = \sqrt {18-11} = \sqrt {7}

Thus the radius of director circle = \sqrt {7} \times \sqrt 2 = \sqrt {14}

Posted by

himanshu.meshram

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025, NEET, CUET UG Dates Live: NTA exam calendar awaited at nta.ac.in
anam-khan

JEE Main 2025 session 1 exam in the last week of January; registration details
anam-khan

Over 656 UPSC, JEE, NEET, other coaching aspirants refunded more than Rs 1 crore: Govt

Latest Question