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Answers (3)

@Deepak Garg

good approach.

since you should take assumption x,y are real numbers.

and using that assumption, since x^2-y^2=0  it implies x = y or x = -y.

also xy = -1/2 and since x,y are real it implies x = -y.

it means -\:x^2\:=\:\frac{1}{2}

so x\:=\:\frac{1}{\sqrt{2}}\:or\:x\:=\:-\:\frac{1}{\sqrt{2}}\:and\:x=\:-y

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Kshitij

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@Deepak Garg

(x+y)(x-y) = 0.

x and y are real numbers, it implies as xy = - 1/2 , x+y = 0 is only possiblity.

now x\:=\:\frac{1}{\sqrt{2}}\:or\:x\:=\:-\:\frac{1}{\sqrt{2}}\:and\:x=\:-y

Posted by

Kshitij

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so roots are (x,y ) = (\frac{1}{\sqrt{2}},-\:\frac{1}{\sqrt{2}}\:) or (-\:\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}}\:)

Posted by

Kshitij

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