Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • What will be the moment of inertia of a ring whose mass is not uniformly distributed? Given that the density of the material is <img alt="\rho" src="http://entrancecorner.oncodecogs.com/gif.la

What will be the moment of inertia of a ring whose mass is not uniformly distributed? Given that the density of the material is \rho and the radius is R, the total mass of the ring is M

Option: 1

\frac{MR^2}{2}


Option: 2

MR^2


Option: 3

\frac{MR^2}{\rho}


Option: 4

\frac{MR^2}{2\rho}


Answers (1)

best_answer

The moment of inertia in both the cases i.e., when mass is uniformly distributed or non-uniformly distributed is the same. Because \int dm = M is same in both cases. So, the answer will me MR2

Posted by

Ritika Jonwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions