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  • When 12.2 g of benzoic acid is dissolved in 100g of water , the freezing frequency point of solution was found to be <img alt="-0.93^{\circ}C (K_f(H_2O)=1.86 K kg mol^{-1})" src="https://entrancecorner.codecogs.com/gif.latex?-0.93%5E%7B%5Ccirc%7DC

When 12.2 g of benzoic acid is dissolved in 100g of water , the freezing frequency point of solution was found to be -0.93^{\circ}C (K_f(H_2O)=1.86 K kg mol^{-1}). The number of benzoic acid molecukes associated (assuming 100% association) is _______
Option: 1 2
Option: 2 -
Option: 3 -
Option: 4 -

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best_answer

\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{i} \times \mathrm{k}_{\mathrm{f}} \times \mathrm{m}

0-(-0.93)=\mathrm{i} \times 1.86 \times \frac{12.2}{122 \times 100} \times 1000

\\\mathrm{i}=\frac{0.93}{1.86}=0.5 \\\\\ \mathrm{n} \mathrm{PhCOOH} \rightarrow(\mathrm{PhCOOH})_{\mathrm{n}} \\\\ \mathrm{i}=1+\left(\frac{1}{\mathrm{n}}-1\right) \alpha \\ \frac{1}{2}=1+\left(\frac{1}{\mathrm{n}}-1\right) \times 1 \\\\\Rightarrow \mathrm{n}=2

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sudhir.kumar

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