Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P, the moles of HCl (g) formed is equal to?

When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), each at S.T.P, the moles of HCl (g) formed is equal to?

Answers (1)

\frac{1}{2}H_2 +\frac{1}{2}Cl_2 \rightarrow HCl

moles of H_2 available =1

moles of Cl_2 available=\frac{1}{2}

Moles of HCl formed are stoichiometry will be 1.

Posted by

lovekush

View full answer

Similar Questions

Latest Question