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  • When resonance is produced in a series LCR circuit, then which of the following is not correct ? Option: 1 Current in the

When resonance is produced in a series LCR circuit, then which of the following is not correct ? 

Option: 1

Current in the circuit is in phase with the applied voltage. 


Option: 2

Inductive and capacitive reactances are equal. 


Option: 3

If R is reduced, the voltage across capacitor will increase. 


Option: 4

Impedance of the circuit is maximum. 


Answers (1)

best_answer

 

 

 

 

 

 

If f_0 is the resonance frequency corresponding to resonant angular frequency \omega _0

then

f_{0}=\frac{\omega_{0}}{2 \pi}=\frac{1}{2 \pi \sqrt{L C}}\left(\because \omega_{0}=\frac{1}{\sqrt{L C}}\right)

At resonance Inductive and capacitive reactances are equal. 

And In LCR circuit Impedance is given as

Z=\sqrt{R^{2}+\left(\omega L-\frac{1}{\omega C}\right)^{2}}

But at resonance Z=R which is minimum

So the statement of option 4 (i.e Impedance of the circuit is maximum. ) is not correct.

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manish

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