Which transition of an electron in the hydrogen atom emits maximum energy is:

Answers (1)

Energy is given by the formula, 

\begin{array}{l} E=\frac{h c}{\lambda} \\ \\ \frac{1}{\lambda}=R Z^{2}\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right] \\ \\ \left.E=R Z^{2} h c \mid \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right] \end{array}

ΔE=−1.51+3.4=1.89eV    When n3?→n2?
ΔE=−0.85+1.51=0.66eV  When n4?→n3?
ΔE=−0.54+0.85=0.31eV  When n5?→n4

The highest energy is for n3 to n2.  

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