A number when successively divide by 3, 5 and 8 leaves remainders 1, 4 and 7 respectively. Find the respective remainders if the order of divisors be reversed.
None of these
Let us say that a number N, when successively divided by a, b, and c leaves a remainder of p, q, and r
=> Before the last division by c, the number must have been of the format of ck + r. Here k is a natural number.
Same logic can be extended to give the value of N.
In this case:
Now, we need to calculate the remainders when the number is successively divided by 8, 3 and 5.
The question will be simpler if I just assume some value of 'k'