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  • A sum of Rs.2310 is due to be repaid at the end of two years. If it has to be repaid in two equal annual instalments (the instalments being paid at the be

 

A sum of Rs.2310 is due to be repaid at the end of two years. If it has to be repaid in two equal annual instalments (the instalments being paid at the beginning of the year) at 10% p a. compounded annually, find the value of each instalment.

 

  • Option 1)

     

    Rs.1210                       

     

  • Option 2)

     

     Rs.1000                  

     

  • Option 3)

     

     Rs.1100                

     

  • Option 4)

     

    Rs.1110  

     

  • Option 5)

     

        Rs.1331

     

Answers (7)

best_answer

 

If a sum of Rs.2310 is due to be repaid at the end of two years. If it has to be repaid in two equal annual installments (the installments being paid at the beginning of the year) at 10% p a. compounded annually, Then the value of each installment is:

Installment = \frac{amount }{no\: o\! f \: installment+\left ( t-1 \right )}\times R\: ^{0}/_{0}

\frac{2310}{2}+ (1) \times \frac{1}{10}

2310 \times \frac{10}{21} = 1100

Posted by

rishi.raj

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1331 is the answer

Posted by

Durga Naresh Eluguri

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Whenever they give installments related

Sum Borrowed = (First installment/ (1+R/100)) + (Second installment/(1+R/100)^2)

2310 = (x/1+10/100) + (x/(1+10/100)^2)

2310 = 10x/11 + 100x/121

x = 2310 * 121/210 = 1331

                          

Posted by

Durga Naresh Eluguri

View full answer

Whenever they give installments related

Sum Borrowed = (First installment/ (1+R/100)) + (Second installment/(1+R/100)^2)

2310 = (x/1+10/100) + (x/(1+10/100)^2)

2310 = 10x/11 + 100x/121

x = 2310 * 121/210 = 1331

                          

Posted by

Durga Naresh Eluguri

View full answer

Whenever they give installments related

Sum Borrowed = (First installment/ (1+R/100)) + (Second installment/(1+R/100)^2)

2310 = (x/1+10/100) + (x/(1+10/100)^2)

2310 = 10x/11 + 100x/121

x = 2310 * 121/210 = 1331

                          

Posted by

Durga Naresh Eluguri

View full answer

Whenever they give installments related

Sum Borrowed = (First installment/ (1+R/100)) + (Second installment/(1+R/100)^2)

2310 = (x/1+10/100) + (x/(1+10/100)^2)

2310 = 10x/11 + 100x/121

x = 2310 * 121/210 = 1331

                          

Posted by

Durga Naresh Eluguri

View full answer

Whenever they give installments related

Sum Borrowed = (First installment/ (1+R/100)) + (Second installment/(1+R/100)^2)

2310 = (x/1+10/100) + (x/(1+10/100)^2)

2310 = 10x/11 + 100x/121

x = 2310 * 121/210 = 1331

                          

Posted by

Durga Naresh Eluguri

View full answer

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