A vessel is full of refined oil. 1/4 of the refined oil is taken out and the vessel is filled with mustard oil. If the process is repeated 4 times and 10 litres of refined oil is finally left in the vessel, what is the capacity of the vessel?

Y = X/4 , final = 10 L

N=4

$X\left ( \frac{1-X}{4X} \right )^{4}= 10L$

$X\left ( \frac{3}{4} \right )^{4}= 10$

$X=\frac{256}{81}\times10= \frac{2560}{81} L$

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