# An alloy contains the copper and aluminum in the ratio 7:4. While making the weapons from this alloy, 12% of the alloy get destroyed. If there are 12 kg of aluminum in the weapon, then the weight of the alloy required is : Option 1) 45kgOption 2) 40kgOption 3) 37.5 kgOption 4) 14.4 kgOption 5) 48 kg

$\inline \left ( \frac{88}{100} \right )\times \left ( \frac{4x}{11} \right )=12$
$\inline x=37.5\, Kg$