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What is the angle between the hands of the clock, when it shows 40 minutes past 6?

Answers (1)

When the minute hand is ahead of the hour hand, the angle between the two hands at M
minutes past H 'o clock =30\left(\frac{M}{5}-H\right)-\frac{M}{2}$ degree

Here H = 6, M = 40 and minute hand is ahead of the hour hand.

\begin{aligned} &\text { Hence the angle }\\ &=30\left(\frac{M}{5}-H\right)-\frac{M}{2}\\ &=30\left(\frac{40}{5}-6\right)-\frac{40}{2}\\ &=30(8-6)-20\\ &=30 \times 2-20\\ &=40^{\circ} \end{aligned}

Posted by

Satyajeet Kumar

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