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What is the angle between the hands of the clock, when it shows 40 minutes past 6?

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When the minute hand is ahead of the hour hand, the angle between the two hands at M
minutes past H 'o clock =30\left(\frac{M}{5}-H\right)-\frac{M}{2}$ degree

Here H = 6, M = 40 and minute hand is ahead of the hour hand.

\begin{aligned} &\text { Hence the angle }\\ &=30\left(\frac{M}{5}-H\right)-\frac{M}{2}\\ &=30\left(\frac{40}{5}-6\right)-\frac{40}{2}\\ &=30(8-6)-20\\ &=30 \times 2-20\\ &=40^{\circ} \end{aligned}

Posted by

Satyajeet Kumar

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