Find the number of factors of x= 2^{\alpha }\times 3^{\beta }\times 6^{\gamma }\times 12^{\delta }

  • Option 1)

    \left ( \alpha +1 \right )\left ( \beta +1 \right )\left (\gamma +1 \right )\left ( \delta +1 \right )

  • Option 2)

    \left ( \alpha +\gamma +2\delta +1 \right )\left ( \beta +\gamma +\delta +1 \right )

  • Option 3)

    \left ( \alpha +\gamma +\delta +1 \right )\left ( \beta +\gamma +\delta +1 \right )

  • Option 4)

    \left ( \beta +\gamma +\delta +1 \right )\left ( \beta +\gamma +\delta +1 \right )

  • Option 5)

    \left ( \alpha +\gamma +2\delta \right )\left ( \beta +\gamma +\delta \right )

Answers (1)

Number of factors of 2^{\alpha }\times 3^{\beta }\times 6^{\gamma }\times 12^{\delta }

            2^{\left ( \alpha +\gamma +2\delta \right )}\times 3\left ( \beta +\gamma +\delta \right )

No. of factors= \left ( \alpha +\gamma +2\delta +1 \right )\left ( \beta +\gamma +\delta +1 \right )

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