Find the remainder obtained when 10! + 111 is divisible by 143.

  • Option 1)

    0

  • Option 2)

    6

  • Option 3)

    7

  • Option 4)

    5

  • Option 5)

    111

Answers (4)

Remainder\: of \:\frac{ \left ( 10!+11 \right )}{143}

\Rightarrow \: \: \: \:\frac{ \left ( 10! \right )}{143}+\frac{\left ( 111 \right )}{143}

\Rightarrow \: \: \: \: \frac{\left ( 720\times 5040 \right )}{143}+111= \frac{\left ( 32+111 \right )}{143}

                0 remainder

S Shreya

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